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Multiplying two selected 3-digit numbers
(middle digit 3)
- Select a 3-digit number with a middle digit of 3 (last digit not zero).
- Choose a multiplier with the same first two digits, whose third digit sums to 10 with the third digit of the first 3-digit number.
- The last two digits will be the product of the third digits:
_ _ _ _ X X.
- The third digit from the right will be 2:
_ _ 2 _ _.
- The next digit to the left will be 7 times the first digit of the number plus 1 (keep carry):
_ _ X _ _ _.
- The first digits will be the square of the first digit plus the carry: X X _ _ _ _.
As you determine the digits in the answer from right to left, repeat them to yourself at each step until you have the whole answer.
Example:
- If the first number is 631, choose 639 as the second number (same first digits, third digits add to 10).
- 1 × 9 = 09 (multiply the third digits) - last two digits:
_ _ _ _ 0 9.
- The third digit from the right is 2:
_ _ 2 _ _ _.
- 7 × 6 = 42, 42 + 1 = 43 (the next digit to the left is 7 times the first digit plus 1 (keep carry 4):
_ _ 3 _ _ _ .
- 6 × 6 = 36; 36 + 4 = 40 ( the first digits are the square of the first digit plus the carry:
4 0 _ _ _ _.
- >So 631 × 639 = 403209.
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