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Multiplying two selected 3-digit numbers
(middle digit 4)
- Select a 3-digit number with a middle digit of 4 (last digit not zero).
- Choose a multiplier with the same first two digits, whose third digit sums to 10 with the third digit of the first 3-digit number.
- The last three digits will be 0 and the product of the third digits: _ _ _ 0 X X.
- The third digit from the right will be 9 times the first digit + 2 (keep the carry): _ _ X _ _.
- The first two digits will be the square of the first digit plus the carry: X X _ _ _ _.
As you determine the digits in the answer from right to left, repeat them to yourself at each step until you have the whole answer.
Example:
- If the first number is 541, choose 549 as the second number (same first digits, third digits add to 10).
- Last three digits: 0 and the product of the third digits:
1 × 9 = 9: _ _ 0 0 9
- Next digit: 9 times the first digit + 2:
9 × 5 = 45, 45 + 2 = 47 (keep carry 4):
_ _ 7 _ _ _
- First two digits: square the first and carry:
5 × 5 = 25, 25 + 4 = 29: 2 9 _ _ _ _
- So 541 × 549 = 297009.
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